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Are We the One Whom We See in the Reflection of Mirror?

Are we the one whom we see in the reflection of mirror?

Yes we are! Because where I go, there I am. So, if I look in the mirror and see me , the mirror reflected what I see, and I see me. Theirs no getting away from me so i try and do my best to be ok when i see the reflection from the mirror of me.

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What's the difference between scattering and reflection?

Reflection and scattering are two phenomenon observed in a lot of systems. Reflection is the procedure of diversion of a path of a particle or a wave owing to a non-interacting collision. Scattering is a procedure where interaction between the two colliding particles occurs. Both of these phenomena are extremely important in fields such as mechanics, geometrical optics, physical optics, relativity, quantum physics and various other fields. Scattering is the course where waves get deviated due to certain anomalies in the space.The reflection is mainly govern by the law that the angle of event is equal to the angle of reflection at any given point.

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Are the OWS kids a reflection of our Fatherless society?

Where else are they going to learn camping skills?

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Reflection relating two subspaces

Let \$E\$ be an Euclidian vector space and \$S_1,S_2\$ two subspaces of same dimension \$k\$. Assume that \$E = S_1 oplus S_2\$. Then there exists \$f\$ an orthogonal symetry such that \$f(S_1)=S_2\$ and \$f(S_2)=S_1\$.Proof: Let \$P\$ be the matrix of the scalar product on \$E\$, and choose a basis of \$S_1\$ and a basis of \$S_2\$ such that \$P\$ has the form : \$\$ P = beginbmatrix I_k & C ^tC & I_k endbmatrix.\$\$ Let \$A\$ be a \$k times k\$ invertible matrix and \$f\$ be an endomorphism of \$E\$ such that its matrix is : \$\$ f = beginbmatrix 0 & A^-1 A & 0 endbmatrix.\$\$ Then \$f\$ is a symetry such that \$f(S_1)=S_2\$ and \$f(S_2)=S_1\$. But \$f\$ is orthogonal iff \$\$^t f.P.f = P,\$\$ that is, \$\$beginbmatrix ^tA.A & ^tA.^tC.A^-1 ^tA^-1.C.A & ^tA^-1.A^-1 endbmatrix = beginbmatrix I_k & C ^tC & I_k endbmatrix.\$\$ Which means that \$A\$ is orthogonal and \$CA\$ is symetric. So if \$A\$ is the inverse of the orthognal part of \$C\$ in the polar decomposition, then \$f\$ is an orthogonal symetry.In the general case, if \$S_1\$ and \$S_2\$ have an intersection. Denote \$S = S_1 cap S_2\$, and write \$S_1 = S oplus^perp T_1\$ and \$S_2 = S oplus^perp T_2\$. Then \$E = S oplus^perp (T_1 oplus T_2)\$. Now choose \$f : E

ightarrow E\$ such that \$f\$ switchs \$T_1\$ and \$T_2\$ on \$T_1 oplus T_2\$ as above and such that \$f\$ is the identity on \$S\$.

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The Countdown Reflection

"The Countdown Reflection" is the 24th and final episode of the fifth season of The Big Bang Theory. It first aired on CBS on May 10, 2012. It is the 111th episode overall. In the episode, featuring astronaut Mike Massimino, Howard and Bernadette get married before Howard goes to space. "The Countdown Reflection" received 13.72 million views in the U.S. and garnered mostly positive reviews

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How to write and start a reflection essay?

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